# VSEPR shape of XeF_{4}

## How to find the shape of XeF_{4}using VSEPR theory?

Step 1: Use lewis structure guidelinesto draw the lewis structure of XeF_{4}.

Step2: Apply VSEPR notation, A X E

A=Number of central atoms

X=Number of surrounding atoms

E= Number of lone pairs on central atom

For the above molecule VSEPR notation will be AX_{4}E_{2}

Step 3: Use VSEPR table to find the shape.
AX_{4}E_{2} has square planar shape. So the shape of XeF_{4} is square planar

Download a copy of VSEPR shapes table here

## Bond angle in XeF_{4}

Bond angle of F-Xe-F bond in this^{}molecule is 90º .The representation is shown below.

Image courtesy:wikipedia.org